Blaze Labs Research Menu
Location: Food for Thought > The EMRP Gravity Theory > Radiation within lifters
Food for Thought
The Particle Part I
The Particle Part II
Unified Theory Foundations
The EMRP gravity theory
Does a non-linear electric field gradient generate gravity? Generating X-rays
EHD Thrusters
EHD thruster collection
Thrusters performance
Lifters in vacuum
Full mathematical analysis (PDF) Ionocraft patent (HTML) Lifter D.O.E. Autonomous thruster project Autonomous thruster calculator Electromagnetic Kinetic Analyser
New Energy Research
Free Energy & Perpetual motion Aquafuel™ generator Transmutation of carbon New fuel from water & carbon
Introduction 01: Inertia device 02: Teflon coated EHD thruster 03: Lightweight hv supply 04: Remote controlled lifter 05: Radiation tests on lifters 06: Ionocrafts vs Lifters 07: Heated cathode lifter 08: Zinc vs Aluminium collector 09: Measuring pulsed dc sources 10: EM Magnus effect 11: Gravity Shielding 12: Thruster gas tests 13: High power hv power supply 14: 100g payload lifter design 15: Cockcroft Walton multiplier 16: 300kV helical resonator 17: 50kV lab power supply 18: Ion Triodes 19: Blazelabs Resonant Multipliers 20: Project RX-7 Instrumentation
Blaze Labs Wiki Links Database PDF Library Periodic table
Contact us

The EMRP Gravity Theory

By Engineer Saviour Borg - Blaze Labs Research

Radiation within lifters

When an electron hits the target so hard on its inner shell, the target material will radiate an EM wave of energy, equal to the energy difference between the innermost and the next shell called K & L1 respectively.

Luckily for us, the air molecules in the atmosphere make it impossible for any electron to travel the whole path from emitter to collector without any collision, in fact there would be millions of such collisions and the electrons can never obtain very high speeds, enough to generate any radiation upon impact. My latest tests for radiation within lifters confirmed no radiation when lifters are powered in air.

The following calculations apply only in pure vacuum.

For aluminium (our foil target), K = 1.56 keV , and L1 = 0.118 keV
The energy difference between the two shells is 1.442 keV.

So, when a charge of sufficient energy hits the aluminium foil, an energy packet of 1.442 keV will be released.

Using E = hf
1.442E3 x e/h = f

This gives f = 3.486E17 Hz, which happens to be the so called 'soft X-ray' band.

Alternatively, knowing the atomic number for Al (Z=13), approximate values can be found. Energy released by an electron shift from L to K = (Z-1)2 * 10.2 eV = 1.46 keV, and f=E/h gives 3.55E17 Hz.

AL EM spectrum

previous home next